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3x^2+5x-6=-2x^2-6x+7.
We move all terms to the left:
3x^2+5x-6-(-2x^2-6x+7.)=0
We get rid of parentheses
3x^2+2x^2+6x+5x-7.-6=0
We add all the numbers together, and all the variables
5x^2+11x-13=0
a = 5; b = 11; c = -13;
Δ = b2-4ac
Δ = 112-4·5·(-13)
Δ = 381
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{381}}{2*5}=\frac{-11-\sqrt{381}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{381}}{2*5}=\frac{-11+\sqrt{381}}{10} $
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